Uva problem solution 11349 - Symmetric Matrix

problem link:

Discuss: in this problem you have to check weather a element less then zero or mat[i][j] and mat[n-1-i][n-1-j]  is not equal. if this happen then this matrix is non symmetric else it is symmetric matrix




#include<bits/stdc++.h>
using namespace std;
int main()
{
    long long n,i,j,flag,t,k;
    cin >>t;
    for(k=1;k<=t;k++)
    {
        long long mat[101][101];
        flag=0;
        char str[10];
        cin >>str>>str>>n;
        for(i=0;i<n;i++)
        {
            for(j=0;j<n;j++)
            {
                cin >>mat[i][j];
                if(mat[i][j]<0)
                    flag=1;
            }
        }
         for(i=0;i<n;i++)
        {
            for(j=0;j<n-i;j++)
            {

                if(mat[i][j]!=mat[n-1-i][n-1-j])
                {
                                        flag=1;
                   break;
                }
            }
        }
        cout <<"Test #"<<k<<':';
        if(flag)
            cout <<" Non-symmetric."<<endl;
            else
                cout <<" Symmetric."<<endl;

    }
    return 0;
}