Uva problem solution 11455 - Behold my quadrangle

problem linK:


Discuss:For Square All sides are equal. For Rectangle Opposite Sides are equal. In this problem opposite sides may be any of two from a,b,c,d such as a b or a c . For Quadrangle sum of all three sides are greater than rest of one side 
tyr yoursefl before see the code

 

 #include<bits/stdc++.h>
using namespace std;
int main()
{

    long long t,l,l1,w,w1,i;
    scanf("%lld",&t);
    for(i=0;i<t;i++)
    {
        scanf("%lld %lld %lld %lld",&l,&w,&l1,&w1);
        vector<int>vec;
        vec.push_back(l);
        vec.push_back(l1);
        vec.push_back(w);
        vec.push_back(w1);
        sort(vec.begin(),vec.end());
        if((l==w&&w==l1&&l1==w1))
            printf("square\n");
        else  if((vec[0]==vec[1])&&(vec[2]==vec[3]))
            printf("rectangle\n");
            else if(l<l1+w+w1&&l1<l+w+w1&&w<l+l1+w1&&w1<l+l1+w)
                printf("quadrangle\n");
            else
                printf("banana\n");

    }
    return 0;
}